Answer: Rate(mm/h) = (diameter[mm]/time[min] X60
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What is the formula for diffusion rate?
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Mon Dec 09 2019 · Graham's law states that the rate of diffusion or effusion of a gas is inversely proportional to the square root of its molar mass. See this law in equation form below. r ∝ 1/ (M)½. or. r (M)½ = constant. In these equations r = rate of diffusion or effusion and M = molar mass .
where (D) refers to the diffusion coefficient and (dC/dx) is the gradient (and is a derivative in calculus). So Fick’s First Law fundamentally states that random particle movement from Brownian motion leads to the drift or dispersal of particles from regions of high concentration to low concentrations – and that drift rate or diffusion rate is proportional to the gradient of density but ...
Sat Aug 15 2020 · 1. Using Graham's law of diffusion: ( Rate 1 /Rate 2 ) = ( Mass 2 /Mass 1) 1/2 (RateF 2 /RateCl 2) = (70.9g/32g) 1/2 = 1.49. Fluorine gas is 1.49 times as fast as chlorine gas. 2. Using Graham's law of diffusion: ( Rate 1 /Rate 2 ) = (Mass 2 /Mass 1) 1/2 (Rate A /Rate B) = (Mass B /Mass A) 1/2. 0.75 = (32g/Mass A) 1/2. 0.75 2 =(32g/Mass A) Mass A = (32g/0.5625) Mass A = 56.8888g. 3.
First law of Diffusion. In the modern mathematical form the Fick’s first law of diffusion is: \( N_{i} = -D_{i} ∇ c_{i}\) Here for species \( i N _{i}\) is the molar flux (mol \(m^{-2} s^{-1 }\)) \(D_{i}\) is the diffusion coefficient ( \(m^{-2} s^{-1}\)) and \(c_{i}\) is the concentration (\(mol m^{-3}\)).
Each model of diffusion expresses the diffusion flux through concentrations densities and their derivatives. Flux is a vector ${\displaystyle \mathbf {J} }$ representing the quantity and direction of transfer. The transfer of a physical quantity ${\displaystyle N}$ through a small area ${\displaystyle \Delta S}$ with normal ${\displaystyle \nu }$ per time ${\displaystyle \Delta t}$ is ${\displaystyle \Delta N=(\mathbf {J} \nu )\ \Delta S\ \Delta t+o(\Delta S\ \Delta t)\ }$ where ${\displaystyle (\mathbf {J} \nu )}$ is the inner product
Each model of diffusion expresses the diffusion flux through concentrations densities and their derivatives. Flux is a vector ${\displaystyle \mathbf {J} }$ representing the quantity and direction of transfer. The transfer of a physical quantity ${\displaystyle N}$ through a small area ${\displaystyle \Delta S}$ with normal ${\displaystyle \nu }$ per time ${\displaystyle \Delta t}$ is ${\displaystyle \Delta N=(\mathbf {J} \nu )\ \Delta S\ \Delta t+o(\Delta S\ \Delta t)\ }$ where ${\displaystyle (\mathbf {J} \nu )}$ is the inner product and ${\displaystyle o(\cdots )}$ is the little-o notation. If we use the notation of vector area ${\displaystyle \Delta \mathbf {S} =\nu \ \Delta S}$ then ${\displaystyle \Delta N=(\mathbf {J} \Delta \mathbf {S} )\ \Delta t+o(\Delta \mathbf {S} \ \Delta t)\ .}$ The dimension of the diffusion flux is [flux] = [quantity]/([time]·[area]). The diffusing physical quantity ${\displaystyle N}$ may be the number of particles mass energy electric charge or any other scalar extensive quantity. For its density ${\displaystyle n}$ the diffusion equation has the f...
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