Answer: +6
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What is the oxidation state of sulfur in H2SO4?
Sun Dec 31 2017 · H2SO4 Oxidation number of H = + 1 Oxidation number of O = -2 Let oxidation number of sulfur be X . Then 2 x (+1) + X + 4 x (-2) = 0 Solving we get +2 + X - 8 = 0 X = +6 Thus oxidation number of sulfur in H2SO4 is + 6 . Hope it helped!
Answer and Explanation: The compound H2SO4 H 2 S O 4 is a neutral compound. That means the algebraic sum of all the anion or cation numbers is zero. We have the ions for two hydrogen ions (+1...
So overall oxidation number of sulphur is - 8+2=-6 . But H2SO4 is a neutral compound to neutralize this compound sulfer show the overall valence of +6.Hence it shows +6 charge to stable the compound. 1.6K views View 1 Upvoter
H2SO4 is a compound and as such does not have an oxidation number. The individual atoms in this compound have oxidation number + 1 for each hydrogen atom + 6 for sulfur and …
Oxidation state of hydrogen = + 1 Oxidation state of oxygen = -2 Let the oxidation state of sulphur be x We know that the sum of oxidation state of all atoms in a compound is zero.
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